1.66x^2+10x-64=0

Solution for 1.66x^2+10x-64=0 equation:

1.66x^2+10x-64=0

a = 1.66; b = 10; c = -64;
Δ = b2-4ac
Δ = 102-4·1.66·(-64)
Δ = 524.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-\sqrt{524.96}}{2*1.66}=\frac{-10-\sqrt{524.96}}{3.32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+\sqrt{524.96}}{2*1.66}=\frac{-10+\sqrt{524.96}}{3.32}
$